This is demonstrated below:įrom the table, we can observe that p(z=0.80) = 0.7881 and p(z=-1.2) = 0. We are required to calculate the probability of z being between -1.2 and 0.80. Standard Normal Distribution Tables STANDARD NORMAL DISTRIBUTION: Table Values Re resent AREA to the LEFT of the Z score. ![]() We can also interpret this as – there is a 97.72% probability that the dividends paid by the company will be below $14. This means that 97.72% of observations lie below a z-score of 2 (2 standard deviations). Look for a z-score in the first column, and note the corresponding F(Z) value. We can look up the z-score of 2 in the above table. If the company pays a dividend of $14 this year, its z-score is 2 indicating that the current dividends are 2 standard deviations above the mean. The dividends paid by a company every year are normally distributed with a mean of $10 and a standard deviation of $2. ![]() In the above table, F(Z) is the probability that a variable from a standard normal distribution will be less than or equal to Z. The following z-table shows the probabilities for z values ranging between – 3 and 3. The standard normal table shows the area (as a proportion, which can be translated into a percentage) under the standard normal curve corresponding to any Z-score or its fraction, i.e., the probability of observing a z-value that is less than the given value. ![]() Once we have the z-scores, we can use the standard normal table to calculate the probabilities.
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